IMO 1981
IMO 1981 — 6/6 solved, 1 verified.
IMO 1981
Official IMO 1981 problems · 6/6 solved, 1 verified.
| # | Status | Time |
|---|---|---|
| 1 | solved | 13m46s |
| 2 | solved | 11m36s |
| 3 | solved | 8m08s |
| 4 | solved | 8m32s |
| 5 | solved | 3m47s |
| 6 | ✓ verified | 7m05s |
Problem 1 solved · 13m46s · Solution →
$\displaystyle P$ is a point inside a given triangle $\displaystyle ABC$. $\displaystyle D, E, F$ are the feet of the perpendiculars from $\displaystyle P$ to the lines $\displaystyle BC, CA, AB$, respectively. Find all $\displaystyle P$ for which
$\frac{BC}{PD} + \frac{CA}{PE} + \frac{AB}{PF}$
is least.
Problem 2 solved · 11m36s · Solution →
Let $\displaystyle 1 \le r \le n$ and consider all subsets of $\displaystyle r$ elements of the set ${ 1, 2, \ldots , n }$. Each of these subsets has a smallest member. Let $\displaystyle F(n,r)$ denote the arithmetic mean of these smallest numbers; prove that
$F(n,r) = \frac{n+1}{r+1}.$
Problem 3 solved · 8m08s · Solution →
Determine the maximum value of $\displaystyle m^2 + n^2$, where $\displaystyle m$ and $\displaystyle n$ are integers satisfying $m, n \in { 1,2, \ldots , 1981 }$ and $\displaystyle ( n^2 - mn - m^2 )^2 = 1$.
Problem 4 solved · 8m32s · Solution →
(a) For which values of $\displaystyle n>2$ is there a set of $\displaystyle n$ consecutive positive integers such that the largest number in the set is a divisor of the least common multiple of the remaining $\displaystyle n-1$ numbers?
(b) For which values of $\displaystyle n>2$ is there exactly one set having the stated property?
Problem 5 solved · 3m47s · Solution →
Three congruent circles have a common point $\displaystyle O$ and lie inside a given triangle. Each circle touches a pair of sides of the triangle. Prove that the incenter and the circumcenter of the triangle and the point $\displaystyle O$ are collinear.
Problem 6 ✓ verified · 7m05s · Solution →
The function $\displaystyle f(x,y)$ satisfies
(1) $\displaystyle f(0,y)=y+1,$
(2) $\displaystyle f(x+1,0)=f(x,1),$
(3) $\displaystyle f(x+1,y+1)=f(x,f(x+1,y)),$
for all non-negative integers $\displaystyle x,y$. Determine $\displaystyle f(4,1981)$.